Dec 19, 2020 · Question: Q5: A Projectile Is Fired In Such A Way That Its Horizontal Range Is Equal To Three Times Its Maximum Height. What Is The Angle Of Projection? A) 45.0 B) 53.1 C) 63.4 D) 38.7 100 But we're going to assume for this projectile motion-- and really all of the future ones or at least in the basic physics playlist-- we're going to assume that air resistance is negligible. And what that does for us is that we can assume that the time for the ball to go up to its peak height is the same thing as the time that it takes to go down.
Maximum height m --- METRIC --- pm nm microns (µm) mm cm km -- IMPERIAL -- mil 1/16 inch inches feet yards miles - SCIENTIFIC - Planck Bohrs Angstrom light-seconds light-years au parsecs --- OTHER --- points cubits fathoms rods chains football fields furlongs Roman miles nautical miles leagues
Nov 13, 2017 · (a) The maximum height occurs for vertical launch of a projectile, which corresponds to a projection launch angle of 90 degrees. (b) The maximum range of a projectile can be shown to occur for a... A cannon fires its projectile with such an initial velocity and angle of projection that its range is R and the maximum height to which the projectile rises is H. Find the maximum range that can be obtained with the same initial velocity.
The maximum height is where yvel = 0. In your initialization method you have: self.yvel=velocity*sin(theta) You know that yvel goes to zero when 0.98*time equals the initial velocity, or at velocity*sin(theta)/9.8 seconds So you can figure out when you get to that time at your interval. Now since xvel is presumed not to change, the xpos at that time is
The maximum height of the projectile launched at 114 m/s at an angle of 45 degrees with the horizontal is 248.53 m. Approved by eNotes Editorial Team